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12-03-2024
Chemistry

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Give the empirical formula of a hydrocarbon that is 47.44% C, 10.51% H, and 42.05% O by mass. Write the formula with the atoms in the order CxHyOz. You can ignore the charge and phase.
a) C3H4O2
b) C4H10O
c) C2H4O2
d) C5H12O

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