contestada

A 120 g coconut falls 12 m. What is the kinetic energy of the coconut just before it hits the ground?

Respuesta :

Kinetic Energy (Ek) =
[tex]m \times {v}^{2} \div 2[/tex]

Torricelli's Equation
g earth = 10m/s^2

[tex] {v}^{2} = {vo}^{2} + 2g \times delta(s) \\ {v}^{2} = 0 + 2 \times 10 \times 12 \\ {v}^{2} = 240m/s[/tex]

120g = 0.12 kg

Ek = 0.12 x 240/2
Ek = 28.8/2
Ek = 14.4 J