I think that the answer would be 2 out of 36 chance or 1 in 18 chance.
Answer: [tex]\dfrac{2}{39}[/tex]
Step-by-step explanation:
Given : A mini bag of Skittles has 3 lemon, 4 grape, 4 orange and 2 lime Skittles.
Total Skittles = 3+4+4+2=13
Probability of pulling an orange Skittle out first : P(First orange) [tex]=\dfrac{\text{No. of orange skittles}}{\text{Total skittles}}[/tex]
[tex]=\dfrac{4}{13}[/tex]
Since the second skittles is drawn without replacement , so after drawing one skittle , the remaining skittles = 13-1=12
So , P(Second skittle is lime) =[tex]\dfrac{\text{No. of lime Skittles}}{\text{remaining skittles }}[/tex]
[tex]=\dfrac{2}{12}=\dfrac{1}{6}[/tex]
Since the events of pulling any Skittle are independent .
So , P( Orange then lime)= P(First orange) x P(Second skittle is lime)
[tex]=\dfrac{4}{13}\times\dfrac{1}{6}=\dfrac{2}{39}[/tex]
∴ The probability of randomly pulling an orange Skittle out first and eating it and then pulling a lime Skittle out of the bag next = [tex]\dfrac{2}{39}[/tex]
