Use this to find the equation of the tangent line to the curve y=5−3x3 at the point (3,−76) and write your answer in the form: y=mx+b, where m is the slope and b is the y-intercept.

Respuesta :

f(x)=5-3x³
f'(x)=-9x²
f'(3)=-81

y+76= -81(x-3)
y+76=-81x+243
y=-81x+167