adamminecrafter adamminecrafter
  • 13-01-2019
  • Mathematics
contestada

For what values of b, the equation x^2−ax+b=0 has a solution for any value of a? PLEASE I NEED IT SOON!

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SugarMagnolias SugarMagnolias
  • 14-01-2019
I’m not sure about the wording of the question, but wouldn’t it be all real numbers?
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Аноним Аноним
  • 14-01-2019

If you choose [tex] b=0 [/tex] the equation becomes

[tex] x^2-ax = 0 \iff x(x-a) = 0 [/tex]

which always has solutions [tex] x=0,\ x=a [/tex]


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