Answer:
The non-permissible replacement for y in the expression is -1
Step-by-step explanation:
we are given
[tex]y=\frac{b^2}{7b+7}[/tex]
we know that
y is undefined when denominator is 0
so, we can set denominator =0
and then we can solve for b
[tex]7b+7=0[/tex]
Subtract both sides by 7
[tex]7b+7-7=0-7[/tex]
[tex]7b=-7[/tex]
Divide both sides by 7
[tex]b=-1[/tex]
So,
The non-permissible replacement for y in the expression is -1
