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  • 14-09-2019
  • Mathematics
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–27x^6b^9 as a cube of a monomial

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jdoe0001 jdoe0001
  • 14-09-2019

[tex]\bf -27x^6b^9~~ \begin{cases} -27=&-3^3\\ x^6=&x^{2\cdot 3}\\ &(x^2)^3\\ b^9=&b^{3\cdot 3}\\ &(b^3)^3 \end{cases}\implies (-3)^3(x^2)^3(b^3)^3\implies (-3x^2b^3)^3[/tex]

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