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A banked circular highway is designed for traffic moving
at60km/h. The radius of the curve is 200m. Traffic ismoving along
the highway at 40km/h on a rainy day. What isthe minimum
coefficient of friction between tires and road thatwill allow cars
to negotiate the turn without sliding off theroad?

Respuesta :

Answer:

0.063

Explanation:

velocity of the car, v = 40 km/h = 11.11 m/s

radius, r = 200 m

Let the coefficient of friction is μ.

The coefficient of friction relates to the velocity on banked road is given by

[tex]\mu =\frac{v^{2}}{rg}[/tex]

where, v is the velocity, r be the radius of the curve road and μ is coefficient of friction.

By substituting the values, we get

[tex]\mu =\frac{11.11^{2}}{200\times 9.8}[/tex]

μ = 0.063

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