Answer:
4.427 m
Explanation:
We shall consider east as + x- axes and north as + ve y- axes. .
We shall represent every displacement in vector form as follows
D₁ = 5.2 km due west = - 5.2 i
D₂ = 2.1 km due north = 2.1 j
D₃ = 3.7 km towards north east at 30 degree from east
= 3.7 cos30 i + 3.7 sin 30 j = 3.2 i + 1.85 j
Total displacement D = D₁ + D₂ +D₃ +D₄.
- 5.2 i + 2.1 j + 3.2 i + 1.85 j
= - 2 i + 3.95 j
Magnitude of D
D² = (2)² + (3.95)²
= 4 + 15.6025
D = 4.427 m
