Answer:
The charge on the sphere is [tex]1.735\times 10^{- 7} C[/tex]
Solution:
The electric potential on the surface of a sphere of radius 'b' and charge 'Q' is given by:
[tex]V_{sphere} = \frac{Q}{4\pi\epsilon_{o}b}[/tex]
According to the question:
Diameter, b = 0.8 m
Potential of sphere, [tex]V_{sphere} = 39 kV = 39000 V[/tex]
[tex]{4\pi\epsilon_{o}\frac{0.8}{2}\times 39000 = Q[/tex]
Q = [tex]1.735\times 10^{- 7} C[/tex]
