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QUESTION 4 1. What is the empirical formula of a substance that contains 3.630 g of C, 0.7615 g of H, and 1.028 g of O? Carbon Hydrogen 0.7615 Oxygen Fill in each blank with the appropriate whole number.

Respuesta :

Answer:

The empirical formule of the substance is C5H12O

Explanation:

A substance contains 3 different elements

Carbon: 3.63 g

 ⇒ Molar mass of Carbon = 12g/mole

Hydrogen: 0.7615 g

  ⇒ Molar mass of hydrogen = 1g/mole

Oxygen: 1.028 g

  ⇒ Molar mass of oxygen = 16g/mole

Calculate number of moles

moles of hydrogen = 0.7615g / 1g/mole = 0.7615 moles

moles of carbon = 3.63g / 12g/mole = 0.3025 moles

moles of oxygen = 1.028g / 16g/mole = 0.06425 moles

Calculate ratio of moles

We divide by the smallest number of moles

Ratio of hydrogen= 0.7615/0.06425 ≈ 12

Ratio of carbon = 0.3025/ 0.06425 ≈ 5

Ratio of oxygen = 0.06425 / 0.06425 = 1

The empirical formule of the substance is C5H12O

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