13-06-2016
Mathematics

contestada

Find the exact values of cos 0 and sin 0 for -120

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nobillionaireNobley nobillionaireNobley

15-06-2016

[tex]sin (-120) = sin(180-60)=sin60= \frac{ \sqrt{3} }{2} \\ cos(-120)=-cos(180-60)=-cos60=- \frac{1}{2} [/tex]

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