ne8tt6iboosaierylecz
ne8tt6iboosaierylecz ne8tt6iboosaierylecz
  • 15-06-2016
  • Mathematics
contestada

Find an equation of the tangent line to y = 2 sin x at x = π/6

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HomertheGenius
HomertheGenius HomertheGenius
  • 21-06-2016
Equation of the tangent line:
y-y0 = f´(x0)(x-x0)
x0 = π/6,  y0= 2 sin(π/6)= 1
f´(X)=2 cos x
y - 1 = 2 cos(π/6)(x- π/6)
y - 1 = [tex]2 * \frac{ \sqrt{3} }{2} ( x - \frac{ \pi }{6} )[/tex]
y = [tex] \sqrt{3} (x - \frac{ \pi }{6} )+ 1 \\ y= \sqrt{3} x + \frac{1- \sqrt{3} \pi }{6} [/tex] 
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