Answer:
μ = 0.104
Explanation:
Given that
m = 1114 kg
s= 6.7 km = 670 m
Initial velocity ,u = 425 km/h
1 km/h= 0.27 m/s
u= 118.056 m/s
The final velocity of car ,v= 0 m/s
We know that
v² = u² + 2 a s
a=Acceleration
Now by putting the values
0² = 118.056² + 2 x a x 670
a=-\dfrac{118.056^2}{2\times 670} m/s^2
a= - 10.4 m/s²
The acceleration also given as
a = - μ g ( fr = m μ g = - m a)
10.4 = 10 x μ ( take g= 10 m/s²)
μ = 0.104
Therefore the coefficient of kinetic friction will be 0.104 .
