thematthewmills4674 thematthewmills4674
  • 14-02-2020
  • Physics
contestada

Calculate the fraction of methyl isonitrile molecules that have an energy of 160.0 kJ or greater at 510 K .

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boffeemadrid
boffeemadrid boffeemadrid
  • 17-02-2020

Answer:

[tex]4.0932672025\times 10^{-17}[/tex]

Explanation:

[tex]E_a[/tex] = Activation energy = 160 kJ

T = Temperature = 510 K

R = Universal gas constant = 8.314 J/mol K

The fraction of energy is given by

[tex]f=e^{-\dfrac{E_a}{RT}}\\\Rightarrow f=e^{-\dfrac{160000}{8.314\times 510}}\\\Rightarrow f=4.0932672025\times 10^{-17}[/tex]

The fraction of energy is [tex]4.0932672025\times 10^{-17}[/tex]

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