Zoenm04 Zoenm04

11-03-2020
Chemistry

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a sample of neon gas occupies a volume of 2.8 L at 1.8 atm. What would it’s volume be at 1.2 atm ?

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ednorobello92 ednorobello92

11-03-2020

Answer: V= 4.2L

Explanation: To solve for the new volume we use Boyle's Law.

P1V1 = P2V2

Derive for V2 the new volume.

V2 = P1V1 / P2

V2 = 1.8 atm x 2.8 L / 1.2 atm

= 4.2 L

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