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How many grams of sulfur (S8) are required in the preparation of 800.0 grams of sulfur dioxide?

S8 + 802 → 8SO2​

Respuesta :

Answer:

see attached

Explanation:

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Answer: m= 400 g S8

Explanation: To solve for the mass of S8 we will do simple stoichiometry based on the balanced equation.

First convert mass of SO2 to moles. Next do the mole ratio. Between SO2 and S8, this will change the moles of SO2 to moles of S8. Convert moles of S8 to mass using the molar mass of S8.

Solution attached.

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