Answer:
(4y - 1)(5y + 2)
Step-by-step explanation:
Given
20y² + 3y - 2
Consider the product of the factors of the coefficient of the y² term and the constant term which sum to give the coefficient of the y- term.
product = 20 × - 2 = - 40 and sum = + 3
The factors are - 5 and + 8
Use these factors to split the y- term
20y² - 5y + 8y - 2 ( factor first/second and third/fourth terms )
= 5y(4y - 1) + 2(4y - 1) ← factor out (4y - 1) from each term
= (4y - 1)(5y + 2) ← in factored form
