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A particular celestial body orbits at a particular speed. For every two orbits it makes, another celestial body orbits three times. This orbital resonance would correspond to which musical interval?

Respuesta :

Answer:

Explanation:

frequency  of first body   f₁  = 2 / T  where T is time taken by it for making two orbits

frequency of second body   f₂  = 3 / T

ration of two frequency

f₁ / f₂ = 2 / 3

This ratio is called perfect fifth in musical interval .

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