jashvalecha jashvalecha
  • 14-09-2020
  • Mathematics
contestada

Can someone answer fast.plsss

Can someone answer fastplsss class=

Respuesta :

theditron theditron
  • 14-09-2020

Answer:

a

Step-by-step explanation:

sec (thita) = squrt (5)

squaring on both sides:

sec^2 (thita) = 5 - equation 1

1 + tan^2 (thita) = 5

tan^2 (thita) = 4

tan (thita) = 2.

= tan (thita) - squrt(5)sin(thita)

= 2 - squrt(5) x 2/ squrt(5)

= 0

from eqn - 1

sec(thita) = squrt(5)

cos(thita) = 1/ squrt(5)

sin(thita) = squrt ( 1- 1/(squrt (5))^2)

sin(thita) = 2/ squrt(5) .

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