RecklessNene RecklessNene

15-09-2020
Mathematics

contestada

The perimeter of a rectangle is found by multiplying the sum of the length, shown as I,
and the width, shown as w, by 2. The length of a certain rectangle is 20. Which
inequality shows that the perimeter of this rectangle is less than 57 units?
A.2 (20+w) > 57
B.2 (20 + w) < 57
C.2 (20) (w) > 57
D.2 (20) (w) < 57

Respuesta :

sqdancefan sqdancefan

16-09-2020

Answer:

B. 2(20 + w) < 57

Step-by-step explanation:

Only choices B and D show something "less than 57". Of those, only choice B shows a sum of length and width.

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