Respuesta :

iloveonedirection
[tex] \frac{12ab^2}{15a^2y} \\ \\ \frac{(12:3)b^2}{(15:3)}a^1^-^2 \\ \\ \frac{4b^2}{5}a^-^1 \\ \\ \frac{4b^2}{5a^1} \\ \\ \frac{4b^2}{5a}[/tex]