0000064
0000064 0000064
  • 14-10-2020
  • Mathematics
contestada

Find the LCM of x2 + x,x2-1,x2-x

Respuesta :

anup12222gupta
anup12222gupta anup12222gupta
  • 15-10-2020

Answer:

[tex]first \: \\ x {}^{2} + x \\ = x(x + 1) \\ \\ second \\ {x}^{2} - 1 \\ = (x) {}^{2} - (1) { }^{2} \\ = (x + 1)(x - 1) \\ \\ third \\ x {}^{2} - x \\ = x(x - 1) \\ \\ therefore \: \: lcm = x(x + 1)(x - 1)[/tex]

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