Josaelx Josaelx

15-10-2020
Mathematics

contestada

Find BC round to the nearest tenth

Find BC round to the nearest tenth class=

Respuesta :

limichael2005 limichael2005

15-10-2020

Answer:

6.7

Step-by-step explanation:

Here, we can apply cosine law, [tex]c^2=a^2+b^2-2abcos\theta[/tex]

We the plug in values: [tex](CB)^2+6^2+5^2-2*6*5*cos74[/tex]

and solve that CB is around 6.7

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