The amount of time it takes a water pump to empty a tank varies directly as the capacity of the tank. If it takes a water pump 2.5 hours to empty a tank containing 60,000 gallons of water, how long does it take the same pump to empty a tank containing 108,000 gallons of water?

Respuesta :

Answer: 4.5 hours

Step-by-step explanation: i used cross multiplication.

2.5/x=60,000/108,000

60,000x=270,000

divide 270,000 by 60,000

x=4.5

An equation is formed when two equal expressions. The time the same pump will take to empty a tank containing 108,000 gallons of water is 4.5 hours.

What is an equation?

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Given that the amount of time it takes a water pump to empty a tank varies directly with the capacity of the tank. Therefore, the relationship can be written as,

V ∝ T

V = kT

Substituting the volume and time in the equation,

60,000 gallons = 2.5 hours × k

Solving the equation for k,

k = 60,000 gallons / 2.5 hours

k = 24,000 gallons per hour

Now, the equation for the relationship can be written as,

V = 24,000 gallons per hour × T

Now, the time the same pump will take to empty a tank containing 108,000 gallons of water is,

V = 24,000 gallons per hour × T

108,000 gallons = 24,000 gallons per hour × T

108,000 gallons / 24,000 gallons per hour = T

T = 4.5 hours

Hence, the time the same pump will take to empty a tank containing 108,000 gallons of water is 4.5 hours.

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