Answer:
[tex]963.34\ \text{years}[/tex]
Step-by-step explanation:
[tex]t_{1/2}[/tex] = Half life of carbon = 5730 years
[tex]\dfrac{N}{N_0}[/tex] = Decay rate = [tex]89\%=\dfrac{89}{100}[/tex]
Duration of time passed is given by
[tex]t=t_{1/2}\dfrac{\ln\dfrac{N}{N_0}}{\ln\dfrac{1}{2}}\\\Rightarrow t=5730\times\dfrac{\ln\dfrac{89}{100}}{\ln\dfrac{1}{2}}\\\Rightarrow t=963.34\ \text{years}[/tex]
The scroll is [tex]963.34\ \text{years}[/tex] old.