Answer:
[tex]N_s : N_p = 20 : 1[/tex]
Explanation:
From the question we are told that
The primary voltage is [tex]V_p = 120 \ V[/tex]
The secondary voltage is [tex]V_s = 6 \ V[/tex]
Generally from the transformer equation we have that
[tex]\frac{V_p}{V_s} = \frac{N_p}{N_s}[/tex]
So
[tex]\frac{120}{6} = \frac{N_p}{N_s}[/tex]
=> [tex]\frac{N_p}{N_s} = 20[/tex]
Therefore the ratio of the number of turns in the secondary to the number of turns in the primary is
[tex]N_s : N_p = 20 : 1[/tex]
