8518664 8518664
  • 15-02-2021
  • Mathematics
contestada

given f(x)= 1/3(4-x)^2, what is the value of f(16)

Respuesta :

mathstudent55
mathstudent55 mathstudent55
  • 15-02-2021

Answer:

48

Step-by-step explanation:

f(x)= 1/3(4 - x)^2

f(16) = (1/3)(4 - 16)^2

f(16) = (1/3)(-12)^2

f(16) = (1/3)(144)

f(16) = 48

Answer Link
Аноним Аноним
  • 15-02-2021

The value of [tex]f(16)[/tex] is 48.

Solve: [tex]f(x)=1/3(4-x)^2[/tex],

 

Solution:  

1. Write the equation

[tex]f(x)= 1/3(4 - x)^2[/tex]

2. Substitute 16 into the x

[tex]f(16) = (1/3)(4 - 16)^2[/tex]

3. Simplify

[tex]f(16) = (1/3)(144)[/tex]

4. Multiply

[tex]f(16) = 48[/tex]

Therefore, the value of [tex]f(16)[/tex] is 48.

Answer Link

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