berkshockeysj
berkshockeysj berkshockeysj
  • 16-02-2021
  • Mathematics
contestada

What is the center of the circle for this equation:

x² + (y - 9)² = 25

Respuesta :

2565579
2565579 2565579
  • 16-02-2021

Answer:x=√−y2+18y−56 or x=−√−y2+18y−56

Step-by-step explanation:

x2+(y−9)2=25

Step 1: Add -y^2 to both sides.

x2+y2−18y+81+−y2=25+−y2

x2−18y+81=−y2+25

Step 2: Add 18y to both sides.

x2−18y+81+18y=−y2+25+18y

x2+81=−y2+18y+25

Step 3: Add -81 to both sides.

x2+81+−81=−y2+18y+25+−81

x2=−y2+18y−56

Step 4: Take square root.

x=√−y2+18y−56 or x=−√−y2+18y−56

Answer:

x=√−y2+18y−56 or x=−√−y2+18y−56

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