Answer:
The recoil velocity of the cannon is 2.38 m/s.
Explanation:
Given;
mass of cannonball, m₁ = 8 kg
mass of stationary cannon, m₂ = 1000 kg
initial velocity of the cannonball, u₁ = 300 m/s
initial velocity of the cannon, u₂ = 0
Let the recoil velocity of the cannon, = v
Apply the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
8(300) + 1000(0) = v(8 + 1000)
2400 = v(1008)
v = 2400/1008
v = 2.38 m/s
Therefore, the recoil velocity of the cannon is 2.38 m/s.
