maxinegarza74
maxinegarza74 maxinegarza74
  • 14-05-2021
  • Mathematics
contestada

if g(x)=x+1/x-2 and h(x)=4-x,what is the value of (g.h)(-3)?

Respuesta :

joaobezerra joaobezerra
  • 19-05-2021

Answer:

[tex]g.h(-3) = \frac{14}{5}[/tex]

Step-by-step explanation:

We are given these following functions:

[tex]g(x) = \frac{x + 1}{x - 2}[/tex]

[tex]h(x) = 4 - x[/tex]

Multiplication function:

[tex]g.h(x) = \frac{x + 1}{x - 2} \times (4 - x) = \frac{(x+1)(4-x)}{x - 2}[/tex]

At x = -3

[tex]g.h(-3) = \frac{(-3+1)(4-(-3))}{-3 - 2} = \frac{(-2)(7)}{-5} = \frac{-14}{-5} = \frac{14}{5}[/tex]

So

[tex]g.h(-3) = \frac{14}{5}[/tex]

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