Answer:
Explanation:
Let's call the large box "1" and the smaller box "2". The equation for this works so that momentum is conserved, as the Law states.
[tex][(m_1v_1+m_2v_2)]_b=[m_1+m_2)v]_a[/tex] That says that the momentum of the larger box plus the momentum of the smaller box before the collision has to equal the momentum of the combined masses since they stick together. Filling in:
[(4(12) + 2(0)] = [(4 + 2)v] and
48 + 0 = 6v so
v = 8 m/s to the right
