Clearglass507 Clearglass507

12-09-2021
Mathematics

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Аноним Аноним

12-09-2021

Irrational number has unsolvable root overs.

Last two are now our options

[tex]\\ \bull\tt\dashrightarrow \sqrt{25}=5[/tex]

Hence its not irrotational.

Hence

Option C is irrational.

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