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For a project in his Geometry class, Jordan uses a mirror on the ground to measure
the height of his school's flagpole. He walks a distance of 9.85 meters from his school,
then places a mirror on flat on the ground, marked with an X at the center. He then
steps 2.25 meters to the other side of the mirror, until he can see the top of the
flagpole clearly marked in the X. His partner measures the distance from his eyes to
the ground to be 1.35 meters. How tall is the flagpole? Round your answer to the
nearest hundredth of a meter.

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MrRoyal MrRoyal · Answer 1 · 2021-09-27T20:24:39+02:00

The question is an illustration of similar triangles and equivalent ratios

The height of the flagpole is 5.91 meters

To do this, we make use of the following representations

[tex]h =1.35m[/tex] --- the height measured by his partner

[tex]d = 2.25m[/tex] ---- the distance walked on the other side of the mirror

[tex]D = 9.85m[/tex] --- the distance walked to place the mirror

[tex]H \to[/tex] the height of the flagpole

The height of the flagpole (H) is calculated using the following equivalent ratio

[tex]h : d = H : D[/tex]

Substitute known values

[tex]1.35m : 2.25m = H : 9.85m[/tex]

Express as fractions

[tex]\frac{1.35m }{ 2.25m }= \frac{H }{ 9.85m}[/tex]

Solve for H

[tex]H = 9.85m \times \frac{1.35m }{ 2.25m }[/tex]

[tex]H = 9.85m \times \frac{1.35}{ 2.25 }[/tex]

[tex]H = 5.91m[/tex]

Hence, the height of the flagpole is 5.91 meters

See attachment for illustration

Read more similar triangles and equivalent ratios at:

https://brainly.com/question/8345267