A commercial jet air plane climbs at takeoff with slope m = 3/8. How far in the horizontal direction will the airplane fly to reach am altitude of 12,000 ft above the takeoff point. Will vote great help

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Answer:

12.00001 ft

Step-by-step explanation:

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Answer:

32000

Step-by-step explanation

[tex]\frac{3}{8} = \frac{12000}{x} \\[/tex]

Solve for x