Answer:
[tex]y=2x+3[/tex]
Step-by-step explanation:
First we need to find the slope of the line between these two points.
We do this by applying this slope formula:
[tex]\frac{y^{2}-y^{1} }{x^{2}-x^{1} }[/tex] (might be a bit small, sorry)
Since we are given two ordered pairs we'll declare the pair (-3, -3) as "x1" and "y1" while (0, 3) will be "x2" and "y2".
Lets now plug in the numbers we're given!
[tex]\frac{3-(-3)}{0-(-3)}[/tex]
Remember that two negatives equals a positive, therefore we'll be adding both the negative 3's in the equation. This will come out to:
[tex]\frac{6}{3}[/tex] and can be reduced to just 2
Now that we have the slope of the line, what about the y-intercept where we start?
We will plug in either the "x2" and "y2" or "x1" and "y2" variable into a slope-intercept form equation. For this example I'll just use the "x1" and "y2" variable. (0 as x and 3 as y)
[tex]-3=2(-3)+b[/tex] (remember that we're solving for b!)
Then it's just simple algebra.
[tex]-3=-6+b[/tex]
[tex]3=b[/tex]
Huzzah! We now have our y-intercept for our slope-intercept equation!
Therefore we just plug in the slope for the "m" spot and 3 for the "b" spot.
[tex]y = 2x+3[/tex]
Hope this helped! If you have any questions feel free to ask!
