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  • 15-10-2021
  • Mathematics
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What is the equation of a line that has a slope of 4/5 and passes through the point (-2,4)?

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Heather
Heather Heather
  • 15-10-2021

Answer:

y = [tex]\frac{4}{5}[/tex]x + 5[tex]\frac{3}{5}[/tex]

Step-by-step explanation:

Let's do it in slope-intercept form, it will look like this:

m = slope

b = y -intercept

To find our equation we will plug in the slope, plug in the point given, and solve for b.

y = mx + b

y = [tex]\frac{4}{5}[/tex]x + b

4 = [tex]\frac{4}{5}[/tex](-2) + b

4 = [tex]-\frac{8}{5}[/tex] + b

5[tex]\frac{3}{5}[/tex] = b

Plug the b into our original equation, and there is our answer!

y = [tex]\frac{4}{5}[/tex]x + 5[tex]\frac{3}{5}[/tex]

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