In a bag of m&ms, there are 12 blue,7 browns, 16 red,6 green, 4 yellow, 8 orange.What is the probability of choosing a brown or green candy from the bag

Respuesta :

Answer:

40 percent

Step-by-step explanation:

Answer:

13/53

Step-by-step explanation:

Total number of m&m's = 53

Probability of choosing a brown candy = 7/53

Probability of choosing a green candy = 6/53

Probability of choosing a green or brown candy

= 7/53 + 6/53

=13/53