c8laurarmilymilyn c8laurarmilymilyn
  • 13-01-2017
  • Chemistry
contestada

Suppose you had 10 mol of NaCl and you dissolved it in exactly 3.00 kg of pure water (the solvent). What would be the molality of the solution in mol/kg?

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AbhiGhost
AbhiGhost AbhiGhost
  • 13-01-2017
Molality = number of moles of solute/mass of solvent in kg = 10/3 = 3.34 mol/kg. 
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