The bouncy ball follows a geometric sequence or pattern
- The distance of rebound the 5th time is 0.015625 ft
- The total distance the ball has travelled after this time is 5.328125 feet
The distance of rebound the 5th time
The given parameters are:
- Initial height, a = 16 ft
- Rebound rate = 0.25
The distance at rebound n is represented as:
Hn = a * r^n
At the 5th time, we have:
H5 = 16 * 0.25^5
Evaluate
H5 = 0.015625
Hence, the distance of rebound the 5th time is 0.015625 ft
The total distance travelled
To do this, we calculate H1 to H5
So, we have:
H1 = 16 * 0.25^1 = 4
H2 = 16 * 0.25^2 = 1
H3 = 16 * 0.25^3 = 0.25
H4 = 16 * 0.25^4 = 0.0625
H5 = 0.015625
Add this distances
Total = 4 + 1 + 0.25 + 0.0625 + 0.015625
Total = 5.328125
Hence, the total distance the ball has travelled after this time is 5.328125
See attachment for the picture
Read more about geometric sequence at:
https://brainly.com/question/24643676
