nwjr23110
nwjr23110 nwjr23110
  • 14-04-2022
  • Mathematics
contestada

Find BC in angle ABC
Round to the nearest tenth.

BC=?

Find BC in angle ABC Round to the nearest tenth BC class=

Respuesta :

jimrgrant1 jimrgrant1
  • 14-04-2022

Answer:

BC ≈ 18.7

Step-by-step explanation:

using the sine rule in Δ ABC

[tex]\frac{BC}{sinA}[/tex] = [tex]\frac{AC}{sinB}[/tex] ( substitute values )

[tex]\frac{BC}{sin67}[/tex] = [tex]\frac{20}{sin80}[/tex] ( cross- multiply )

BC × sin80° = 20 × sin67° ( divide both sides by sin80° )

BC = [tex]\frac{20sin67}{sin80}[/tex] ≈ 18.7 ( to the nearest tenth )

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