4025703 4025703
  • 14-04-2022
  • Chemistry
contestada

What is the temperature, in kelvin, of 4.15 moles of a gas at a pressure of 7.30 atmospheres in a 21.7 liter container?

P
V
=
n
R
T


R = 0.0821
a
t
m
⋅
L
m
o
l
⋅
K

Respuesta :

40042
40042 40042
  • 14-04-2022

Answer:

461.91 Kelvin

Explanation:

P = 7.30 atm

V = 21.7 liters

n = 4.15 moles

R = 0.0821 atm

T = ?

PV = nRT

(7.30) (21.7) = (4.15) (0.0821) (T)

158.41 = 0.34 (T)

T = 465.91 Kelvin

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