shay868282 shay868282

15-04-2022
Mathematics

contestada

Solve the equation: (a + 2)^4- 20(a + 2)^2+ 64 = 0

Respuesta :

alainc25 alainc25

15-04-2022

Answer:

Answer is 7.

Step-by-step explanation:

(a + 2)^4- 20(a + 2)^2+ 64 = 0

2a^4- 20(2a)^2+ 64 = 0

16a-20(4a)+64=0

-4a -64 -4a -64

12a-84=0

+84 +84

12a=84

84/12=7

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shaiwsuhstwuegs shaiwsuhstwuegs

15-04-2022

The answer is 7
If needed to be solved to show proof text me

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