Respuesta :

199932

[tex]sin60 = \frac{opp}{hyp} \\ sin60 = \frac{y}{12 } \\ \frac{ \sqrt{3} }{2} = \frac{y}{12} \\ 2y= 12 \sqrt{3} \\ y = 6 \sqrt{3} [/tex]

[tex]cos60 = \frac{adj}{hyp} \\ cos60 = \frac{x}{12} \\ \frac{1}{2} = \frac{x}{12 } \\ 2x = 12 \\ x = 6[/tex]

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