Turnerrocks12 Turnerrocks12
  • 12-09-2022
  • Mathematics
contestada

Range of hx = 2r^2 + 20r +42

Respuesta :

jaisurajk jaisurajk
  • 12-09-2022

Answer: Range: hx>=-8

Step-by-step explanation:

Find the vertex first:

2r^2 + 20r +42=

2(r^2 + 20r/2 +42/2)=

2(r^2 + 10r +21)=

2(r^2 + 10r +25-4)=

2(r^2 + 5r+5r +25-4)=

2(r(r+5)+r(r+5)-4)=

2((r+5)^2-4)=

2(r+5)^2-4*2=2(r+5)^2-8   ==> Vertex: (-(5), -8) ==> (-5, -8)

-8 is when the range starts

Range: hx>=-8

Answer Link

Otras preguntas

THIS SI THE ANSWER TO UR QUESTION 11111
How does the United States use foreign aid to promote foreign policy goals?
this from usatestprep
What is the length of a base of a right triangle with an area of 15 meters and a height of 3 meters? Question 1 options: 5 meters 12 meters 10 meters
A printer is printing photos. For every 8 photos, the printer takes 4 minutes. Complete the table below showing the number of photos and the time it takes to pr
Solve for b can someone help me please
which phrase discribes a feature of groundwatera feeds rivers b provides habitats c makes up 75 percent of fresh waters d used for hydroelectric power ​
please help me with this
What was the nickname given to President Truman's foreign policy towards the Soviet Union?
please urgent please help