andyespinal
andyespinal
14-04-2015
Mathematics
contestada
log6 24 + log6 3 - log6 2
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konrad509
konrad509
14-04-2015
[tex]\log_6 24 + \log_6 3 - \log_6 2=\\ \log_6(24\cdot3)- \log_6 2=\\ \log_672-\log_62=\\ \log_6\dfrac{72}{2}=\\ \log_636=\\ 2 [/tex]
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