derrickharris64
derrickharris64 derrickharris64
  • 15-06-2017
  • Mathematics
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5. Use the discriminant to determine how many real number solutions exist for the quadratic equation –4j2 + 3j – 28 = 0

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Banabanana
Banabanana Banabanana
  • 15-06-2017
–4j² + 3j – 28 = 0
D = b² - 4ac = 3² - 4*(-4)*(-28) = 9 - 448 = -439
D<0  ⇒  j ∈ ∅
No solutions
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