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A force of 50√3 applied to a crate at 30° to the horizontal surface is used to drag the crate through a distance of 7m along the surface. If the work done in dragging the crate is 175 J, the frictional force between the crate and the floor is​

Respuesta :

Answer:

50 N

Explanation:

Work = distance × net parallel force

W = d (F cos θ – f)

175 J = (7 m) (50√3 cos 30° – f)

25 N = 75 N – f

f = 50 N