Respuesta :

lublana

Answer:

0 and 3

Step-by-step explanation:

We are given that an inequality

[tex]-3x-4< 2[/tex]

Adding 4 on both sides of inequality

[tex]-3x-4+4<2+4[/tex]

[tex]-3x< 6[/tex]

Divide by 3 on both sides of inequality

[tex]-x<2[/tex]

[tex]x > -2[/tex]

[tex]x\in(-\infty,-2)[/tex]

The solutions of given inequality are 0 and 3.

Answer:0 and 3

The values that are solutions to the inequality are 0 and 3

The given inequality is:

–3x – 4 < 2

Add 4 to both sides of the inequality:

-3x  -  4 +  4   <  2   +  4

-3x   <   6

Divide both sides by 3:

-3x / 3   <  6/3

-x   <   2

Multiply both sides by -1 and change the symbol to >.

x  >  -2

Therefore, among the options, the values greater than -2 are 0 and 3.

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