Respuesta :
Answer:
The range of the function f(x)=3x²+6x-8 is:
{y|y ≥ –11}
Step-by-step explanation:
The function f(x)=3x²+6x-8 could also be written as:
f(x)=3x²+6x+3-11
f(x)=3(x²+2x+1)-11
f(x)=3(x+1)²-11
as we know that the value of 3(x+1)²≥0
Then, the value of 3(x+1)²-11≥-11
i.e. f(x)≥-11
Hence, the range of the function f(x)=3x²+6x-8 is:
{y|y ≥ –11}
